Question

The smallest number which when perfect square and is dimished by 12,16,18,21,45 is?​

Answer 1

Answer:

First find the smallest number divisible by 12,16,18,21 and 28.

It is the LCM of these numbers.

12=2×2×3=2

2

×3

16=2×2×2×2=2

4

18=2×3×3=2×3

2

21=3×7

28=2×2×7=2

2

×7

LCM=2

4

×3

2

×7=1008

Required number = (L.C.M. of 12, 16, 18, 21, 28) +7

=1008+7

=1015

So the required number is 1015.

If you diminish by 7, it will be divisible by all the given numbers.

Answer 2

Answer:

the correct answer is 12

Step-by-step explanation:

6×2=12