Question

the smallest number with which 3645 must be divided so that it become a perfect square is ?

Answer 1

the smallest no. is 5
$\frac{3645}{5} = 729$
which is square of 27

Answer 2

Hey there ! 
I am Aaditya

Given number is 3645 
Jot down the prime factors of 3645
3645=5*3*3*3*3*3*3

Organising the prime factors into pairs

3645=(3*3)(3*3)(3*3)*5

We observe that only 5 doesnt exist in pair 

So,the smallest number that should be divided from 3645 to make it a perfect square is 5

3645÷5= 729

Thus the resulting number is 729

√729=27 

There fore , 27 is the square root of resulting number 729 

hope helped!

-Regards ,
Aaditya