Question

the smallest of three consecutive integers is added to four times the largest integer;the result so obtained is 15 less than three times the middle integer.Find the integers​

Answer 1

Answer:

Let the three consecutive integers be x,x+1,x+2

ATQ

x+2(x+2)+15=4(x+1)

=3x+19=4x+4

= x=15

..... Hence. The nos. Are 15,15+1=16 and 15+2=17

Step-by-step explanation:

Answer 2

Answer:

Hi, here is your answer

let the smallest integer = x

middle integer = x+1

largest integer = x+2

sum of these integers = x+(x+1)+(x+2)=3x+3

twice the largest integer = 2(x+2)=2x+4

four times the middle integer = 4(x+1)=4x+4

according to the question

x+(2x+4)=(4x+4)-15

=>3x+4=4x-11

=>3x-4x=-11-4

=>-x=-15

=>x=15

so the integer is 15.

Hope this will help you

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Step-by-step explanation: