Question

The smallest of three consecutive integers is added to four times the largest integer, the result so obtained is 15 less than three times the middle number. Find the integers​

Answer 1

Answer:

Answer

Let the three integers be x, x+2 and x+4

Now from the given information, the equation we get is

x+4(x+4)=4(x+2)+729

⇒x+4x+16=4x+8+729

⇒5x−4x=737−16

⇒x=721

So the three consecutive odd integers are,

x=721

x+2=723,

and x+4=725

Therefore, the numbers are 721,723,725.

Step-by-step explanation:

Answer

Let the three integers be x, x+2 and x+4

Now from the given information, the equation we get is

x+4(x+4)=4(x+2)+729

⇒x+4x+16=4x+8+729

⇒5x−4x=737−16

⇒x=721

So the three consecutive odd integers are,

x=721

x+2=723,

and x+4=725

Therefore, the numbers are 721,723,725.