Question

The smallest of three consecutive integers is added to twice the largest, resulting in 15 less than four times the middle integers. Find the integers.

Answer 1

Let the three consecutive integers be x,x+1,x+2
ATQ

x+2(x+2)+15=4(x+1)
=3x+19=4x+4
= x=15
..... Hence. The nos. Are 15,15+1=16 and 15+2=17

Answer 2

Hi, here is your answer

let the smallest integer = x
middle integer = x+1
largest integer = x+2
sum of these integers = x+(x+1)+(x+2)=3x+3
twice the largest integer = 2(x+2)=2x+4
four times the middle integer = 4(x+1)=4x+4
according to the question
x+(2x+4)=(4x+4)-15
=>3x+4=4x-11
=>3x-4x=-11-4
=>-x=-15
=>x=15
so the integer is 15.

Hope this will help you
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