Question

The smallest perfect square number divisible by 5, 6 and 27​

Answer 1

Answer:

8100

Step-by-step explanation:

lcm of 5, 6 and 27 is 270

now 270 is

$270 = 9 \times 30 = {3}^{2} \times 5 \times 2 \times 3$

to make it a perfect square, we need to multiply it with

$5 \times 2 \times 3 = 30$

thus the smallest number is

$270 \times 30 = 8100$

Answer 2

Answer:

16200

Step-by-step explanation:

At First , We need to find LCM of 5 ,6, 27 which is 3*5*2*9 = 180.

Then multiply 180 with 2,5,9

=16200

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