Math, asked by shanusharma1903, 11 months ago

The smallest positive integer for which (1+i/1-i)^n =1 is​

Answers

Answered by Anonymous
3

Answer:

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Answered by silentlover45
0

Answer:

i^n = 1

The smallest integral value of n will be 4.

Step-by-step explanation:

Given:

(1 + i)^n /1 + i = 1

(1 + i)(1 + i)^n / (1 - i)(1 + i) = 1

2i^n/2 = 1

i^n = 1

The smallest integral value of n will be 4.

Hope it is helpful...

silentlover45.❤️

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