The smallest positive integer for which (1+i/1-i)^n =1 is
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Answer:
i^n = 1
The smallest integral value of n will be 4.
Step-by-step explanation:
Given:
(1 + i)^n /1 + i = 1
(1 + i)(1 + i)^n / (1 - i)(1 + i) = 1
2i^n/2 = 1
i^n = 1
The smallest integral value of n will be 4.
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