Question

the smallest positive integer n for which, (1-i/1+i)n²= 1,where i =√-1​

Answer 1

Answer:

Step-by-step explanation:

Given [(1+i)/(1-i)]n = 1

Multiply numerator and denominator with (1+i)

We get [(1+i)(1+i)/(1-i)(1+i)]n = 1

[(1+2i-1)/(1-i2)]n = 1

[(2i)/(1-(-1))]n = 1

(2i/2)n = 1

in = 1

Here the smallest number of n is 4.

Hence option (4) is the answer.

Answer 2

Answer:

4 is the answer

hope it helps