Question

The smallest positive integer n for which (1+i)^2n=(1-i)^2n is

Answer 1

Answer:

Hey mate here is your answer.....

Answer : 2

Explanation :

n=2 , because $\; (1+i)^{2n} = (1-i)^{2n}$

$(\large\frac{1+i}{1-i})^{2n} =1$

$(i)^{2n} =1\;$ which is possible if n=2 $\quad [i^{4} =1]$

hope it's helpful for you....