Question

the smallest positive integer that appears in each of the Arithmetic progressions 5,16, 27, 38, 49,..., 7,20 ,33,46 ,59 and 8 ,22, 36 , 50, 64 is​

Answer 1

Answer:

Right general terms in both series

5 + ( n - 1 ) 11 = 11n - 6

8 + ( n - 1 ) 14 = 14n - 6

So in other words we need smallest positive integer which is 6 more then a multiple of 11 and 14 .

So LCM of 11 and 14 = 154

So number will be 154 + 6 = 160