Question

the smallest possible no. divisible by 2,3,6 & 9 is?​

Answer 1

Step-by-step explanation:

Here’s one method to use:

First, list all the numbers:

2, 3, 4, 5, 6, 8, 9, 10

Next, cross out any number that is a factor of another number

2 × 3 = 6, so cross out 2 and 3

4 is a factor of 8, so cross out 4

5 is a factor of 10, so cross out 5

Now, we have:

#, #, #, #, 6, 8, 9, 10

Look at 6:

2 × 3 = 6

2 is a factor of 8

and

3 is a factor of 9

so cross out 6

Now, we have a much shorter list:

#, #, #, #, #, 8, 9, 10

We only have two numbers that are not co-prime now, 8 and 10:

2 × 5 = 10

2 is a factor of 8, so change 10 to 5

Finally, we end up with:

#, #, #, #, #, 8, 9, 5

What is the product of these three numbers?

8 × 9 × 5 = ???

Answer 2

Answer:

18 is the smallest possible no which will divisible by 2,3,6&9.

Step-by-step explanation:

18/2=9

18/3=6

18/6=3

18/9=2