the smallest resistance obtained by connecting 50 resistance of 0.25 ohm each is
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1/R=1/R₁+1/R₂/R
1/R=1/50+1/0.25=201/50
∴ R=50/201Ω=0.249 Ω
1/R=1/50+1/0.25=201/50
∴ R=50/201Ω=0.249 Ω
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