Question

The smallest value of k for which the equation x^2 +kx+16=0 has real roots

Answer 1

Answer:

K= 8

Step-by-step explanation:

X^2+kx+16=0

It has real roots

-b^2+4ac=0

Here,a=1,b=k,c=16

-k^2+4(1)(16)=0

-k^2+64=0

-k^2=-64

k^2=64

K=8