the smallest value of k for which the equation x^2+kx+9=0 has real roots is
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Answered by
0
Answer:
The given quadratic equation is x
2
−kx+9=0, comparing it with ax
2
+bx+c=0
∴ We get, a=1b=−k,c=9
⇒ It is given that roots are real and distinct.
∴ b
2
−4ac>0
⇒ (−k)
2
−4(1)(9)>0
⇒ k
2
−36>0
⇒ k
2
>36
⇒ k>6 or k<−6
∴ We can see values of k given in question are correct.
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Answer:
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