The smallest value of k for which the equation x² + kx + 9 = 0 has real roots is *
1 point
- 6
6
- 36
- 3
Answers
Answered by
2
Answer:
if the equation has a real root then d=0 so, b ka square -4ac = 0 ,k square -4×1×9 =k square -36 =0 then k square = 36 so, k = √36 therefore k =6
Answered by
2
Step-by-step explanation:
k=6 is your answer friend
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