Question

The smallest value of n for which f(n) = n + n + 41 gives a composite number is

Answer 1

Answer:

Step-by-step explanation:

F(n) =n+n+41

if n=1

F(1)=1+1+41=43 it is a prime number

If n=2

F(2)=2+2+41=45 it is a composite number

So, 2 is the least number so that F(n) = n+n+41 becomes composite number