Question

The smallest value of x for the inequation 6x−2> −6−2x,x∈Z, ​

Answer 1

Answer:

x2−2x−8≤0⇒(x−4)(x+2)≤0

∴xϵ[−2,4]

Roots of the given equation x2+6x+8=0 are - 2,-4

Differentiating the equation, we get 2x+6>0 in the interval [-2,4]⇒it is an increasing function in that interval 

∴minimum value exists at x=−2

At x=−2, smallest value occurs =0

Answer 2

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