Question

The smallest. Value of y in the number 9y8071 such that it is divisible by 11.

Answer 1

Answer:

1

Step-by-step explanation:

To find the shortest way about the no. divisble by 11 is adding the odd place digit and even place digits separately and then subtract the sum of odd place digit sum from even digit sum then if the result is divided by 11 completely then the no. will be divisible by 11.

so 9+8+7=24

y +0+1=y+1

24 - ( y+1)/11= multiple of 11

23- 1=22 which is a multiple of 11

so y=1

Answer 2

Step-by-step explanation:

sum of the digits of odd place=24

sum of the digits of even place=1+y

number is divisible by 11 if the difference of the digits of odd and even place is either 0 or multiple of 11

hence smallest number is

${24 - (y + 1)}{11} = divisible of 11$

23-y= divisible of 11

(y=23)

so that 23-23=0

now

23÷11(remainder=1)

hence 1 is the required number