Question

The smooth rod of mass 10 LG is in equilibrium of walls are fixed. Find the force exerted by wall AB on the rod

Answer 1

Answer:

The answer is 50N.

Explanation:

We can say that:

The force exerted by wall on rod is normal reaction force.

After balancing the forces which are perpendicular to the surface of wall we can find the normal reaction force as

N  =  m g cos 60

N  =  10  ×  10  ×  1/ 2  N  =  50 N

Thus, the force exerted by the wall on the rod is  50 N .