Question

The solid conductor has a cross section area 1 cm square and 2 cm square as shown in the figure a current of 20 and sram entering at a then

Answer 1

A solid conductor has a cross section area 1 cm^2 and 2 cm^2 as shown in the figure. A current of 20 A entering at A. then

a)Current density at A=Current density at B

b)Current density at A>Current density at B

c)Current density at A<Current density at B

d)None of the above

Correct Option is B

Given:

Cross Section Area at A=1 cm^2

Cross Section Area at B=2cm^2

To Find:

Current density at A and B .

Solution:

Formula:

Current Density=Current/Area

So,Current density is inversely proportional to its Area.Which means that if we increase the Area ,the current density decreases .

Since,

Area of A (1cm^2)<Area of B(2cm^2)

Therefore,Current density at A>Current density at B.

Hence Option B is correct.

Answer 2

A solid conductor has a cross-section area of 1 cm^2 and 2 cm^2 as shown in the figure. A current of 20 A entering at A. then

a)Current density at A=Current density at B

b)Current density at A>Current density at B

c)Current density at A<Current density at B

d) None of the above

The correct option is b) Current density at A > Current density at B.

Given:

A solid conductor has a cross-section area of 1 cm^2 and 2 cm^2.

To Find:

The correct statement.

Solution:

To find the correct option we will follow the following steps:

As we know, current density =

$\frac{current}{area}$

Current density at point A =

$\frac{current}{area} = \frac{20}{1 } = 20A {m}^{ - 2}$

Similarly,

Current density at point B =

$\frac{current}{area} = \frac{20}{2 } = 10A {m}^{ - 2}$

Henceforth, the correct option is b) Current density at A > Current density at B.

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