Question

The solid floats in water with 3/5th of its volume immerged in it,
Calculate the density of the solid. (density of water = 1 g cm)
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Answer 1

Answer:

Explanation:

volume immerged=3/5v

volume above water=2/5v

according to archimedes principle

buoyant force=weight of liquid displaced

buoyant force=mg

3/5v×$P_{w}$×g=(2/5v+3/5v)×$P_{B}$×g

$P_{B}$=3/5$P_{w}$

$P_{B}$=0.6×1g/cm

$P_{B}$=0.6g/cm3