Question

The solid is in the shape of a cylinder with two hemispheres stuck to each of its ends asshown in the figure.The radius of the cylinder and hemispheres are equal to ‘r’ cm, if the height of the cylinder is ‘h’ cm. The volume of the solid is
A)πr²(4r+h) cm³
B)πr²(4r/3+h) cm³
C)πr²/3 (4r+h) cm³
D)πr²(2r/3+h) cm³




(πr² pie R square just if didn't get that this not with the problem)
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Answer 1

Answer:

Here is your answer

Step-by-step explanation:

Volume of solid = volume of cylinder + 2 x ( volume of hemisphere )

                          = $\pi$r² h + 2 x 2/3 $\pi$r³ cm³

                          = $\pi$r²  ( h + 2 x 2/3 r )

                          = $\pi$r²  ( h + 4/3 r ) cm³

Answer 2

Answer:

B)  πr²(h + 4r/3 ) cm³ .

Step-by-step explanation:

Given:- The given solid is a cylinder with two hemisphere stuck at each end. The radius of cylinder and hemisphere is r cm and height of cylinder is h cm.

To Find:- The volume of the solid.

Solution:-

We know that,

Volume of a cylinder = π r² h where r is the radius and h is the height.

Volume of a hemisphere = 2/3 π r³, where r is the radius.

Volume of 2 hemispheres = 2/3 π r³ + 2/3 π r³

                                            = 4/3 π r³ cm³

Now, the volume of solid = volume of cylinder + volume of 2 hemispheres

                                          = π r² h + 4/3 π r³ cm³

                                          = π r² (h + 4/3 r) cm³

                                          =  π r² (h + 4r/3) cm³

Therefore, the correct option is B)  πr²(h + 4r/3 ) cm³ .

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