Question

The solubility of a salt in water is 40 at 30 degree Celsius; the amount of water required. To dissolve 120 gm at the same temperature is
A. 400 gm
B. 100 gm
C. 300 gm
D. 500 gm

Answer 1

Answer:

300 g

Explanation:

Correct option is c)

weight of salt = 120 gram,

solubility = 40

solubility  formula

solubility of solute =  weight of solute / weight of solvent * 100

40 = 120/x *100

x = 120*100/40

x=300 g

Hence 300 gm of water is required to prepare a saturated solution.

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Answer 2

Answer: C.300gm

Explanation:

Given values

Solubility of salt= 40

Weight of solute = 120gm

(Solute is minor component in a solution, dissolved in the solvent.)

Solubility is directly proportional to weight of solute and indirectly proportional to the weight of solvent.

Solubility  formula

Solubility of solute =  Weight of solute / Weight of solvent * 100

40 = 120/x *100

x = 120*100/40

x=300 g

Hence 300 gm of water is required to prepare a saturated solution.

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