Question

The solubility of a solute 'X' in water is 35 g in 100 of water. The density of the solution is
1.5ml The concentration of in the solution in % m/v

Answer 1

HEY DEAR..

The concentration of the solution =mass of solute / mass of solutions × 100

mass of solutions = masa of solute + mass of solvent

=》 35+ 100 = 135.

The concentration of solutions=》 35 / 135 × 100

35 × 50/ 27 = 1750 / 27

64.8148..%

HOPE ITS HELPFUL

BE BRAINLY

Answer 2

Answer:

First we need to find the volume. For that we can use the formula

density = mass/volume (definition of density)

1.5 = 135/volume (135 is the combined mass of the solute and solvent)

volume = 135/1.5 = 90 (the reason why I left out the units is that I'm not       really sure of them)

now divide mass of solute by volume = 35/90

find percentage = (35 * 100) /90 = 350/9 = 38.8888.....% ~ 38.88%

Therefore 38.88% is the answer.