Question

The solubility of a substance in water is 40 g
/ 100 g. The maximum amount of solute
required to prepare a saturated solution in
25g of water is 10 g​

Answer 1

Explanation:

weight of salt = 90 gram,

solubility = 50

sing formula

solubility of solute =

weightofsolventinsaturatedsolution

weightofsoluteinsaturatedsolution

×100

or 50=

weightofsolventinsaturatedsolutio

90gm

×100

so weight of solvent in saturated solution =

50

90gm

×100=180gm

Hence 180 gm of water is required to prepare a saturated solution.