the solubility of a substance in water is 40. what is its maximum amount of solute required to prepare a saturated solution with 50g of water
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weight of salt = 90 gram , solubility = 50
using formula solubility of solute = weight of solvent in saturated solution
weight of solute in saturated solution
X100 or 50 = weight of solvent in saturated solitude
90gm x100 so weight of solvent in saturated solution 50
90gm * 100 = 180gm
Hence 180 gm of water is required to prepare a saturated solution
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