Question

the solubility of a substance is 40 what is the maximum amount of solute required to prepare a saturated solution of 50g of water?​

Answer 1

Answer:

weight of salt = 90 gram,  

solubility  = 50

sing formula  

solubility of solute =  

weightofsolventinsaturatedsolution

weightofsoluteinsaturatedsolution

​  

×100

or 50=  

weightofsolventinsaturatedsolutio

90gm

​  

×100

so weight of solvent in saturated solution =  

50

90gm

​  

×100=180gm

Hence 180 gm of water is required to prepare a saturated solution.

Explanation:

Answer 2

Answer:

hence 180 gm of water is required to prepared a saturated solution