Chemistry, asked by Asmitabhosale, 7 months ago

The solubility of AgBr in water is
1.28x10-⁵ moles/ dm³ at 298 K calculate the solubility product of AgBr at the same temperature

Answers

Answered by MaN0007

2

The answer is s^+2 so answer is 1.6384x10^-10

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