the solubility of AgBr is 5.2 into 10^-13. calculate its solubility in Mol dm^-3 and g dm^-3. molar mass of AgBr =187.8 g mole^-1
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Answered by
3
I think its answer is 450 mole .......!...............
nimishadeshmukh1234:
it's answer is 1.34 into 10^-4 g dm ^-4 but I don't know how to solve
no it is wrong....
you know very welll.
ok .. tell me thanks..
but how
Answered by
6
answer 1.34
hope you get it
hope you get it
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