Question

the solubility of C6H12O6 IN 100 g of water is ....................
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Answer 1

Answer:

Molality of a solution is defined as the number of moles of solute dissolved per kg of solvent.

C

6

H

12

O

6

=10% by weight.

Thus in 100 g solution mass of glucose = 10 g and of water =90 g

Number of moles of glucose =

molar mass

mass

n=

180

10

=

18

1

mol

Mass of solvent = 90 g= 0.09 kg

Molality, m=

0.09

(

18

1

)

m=

18×9

100

=0.617 molal≈0.6 molal

The molality of a solution of glucose (C

6

H

12

O

6

) in water is labelled as 10% by weight is 0.617 molal.

Answer 2

The molality of a solution of glucose (C6H12O6) in water is labelled by as 10percent by weight is 0.617 molal.