The solubility of CaF2 In a solotion of 0.1M of Ca(No3)2 is given by
Answers
Written in mathematics as √2 or 21⁄2, is the positive algebraic number that, when multiplied by itself, equals the number 2. Technically, it is called the principal square root of 2, to distinguish it from the negative number with the same property.
The length of a diagonal across a square with sides of one unit of length; this follows the Pythagorean theorem. It was probably the first number known to be irrational.[citation needed]
As a good rational approximation for the square root of two, with a reasonably small denominator.
the OEIS consists of the digits in the decimal expansion of the square root of 2, here truncated to 65 decimal places:
The solubility of CaF₂ in a solution of 0.1 M is 3.08 × 10⁻⁶ M.
Explanation:
The chemical equation of the reaction is given as:
CaF₂ ⇄ Ca⁺² + 2F⁻
When 1 mole of salt is dissolved then 1 mole of Ca⁺² and 2 moles of F⁻ is formed.
The Ksp is given as:
Ksp = [Ca⁺²] × [F⁻]²
Where,
[Ca⁺²] = (0.1 + S) M
[F⁻] = S
Ksp = 3.9 × 10⁻¹¹
On substituting the values, we get,
3.9 × 10⁻¹¹ = (0.1 + S) + 4S²
3.9 × 10⁻¹¹ = 0.1 + 4S²
3.8 × 10⁻¹¹ = 4S²
S² = (3.8 × 10⁻¹¹)/4
∴ S = 3.08 × 10⁻⁶ M