Chemistry, asked by sagarbundi, 8 days ago

the solubility of Hg2I2 in water is 10^-5 M calculate its solubility product?​

Answers

Answered by choudharysoni309
2

Answer:

x^x.y^ys^x+y is a right ans

Answered by rahul123437
0

Solubility product of Hg2I2 is given by   K sp = [Hg^{2+} ][I^{-} ] which is 4×10^{-5}

Explanation:

  • The solubility product is the solid's solubility which is expressed in units of moles per liter (mol/L),and it  is  known as its molar solubility.
  • The solubility constant (Ksp) is also known as the solubility product.
  • When a solid substance is dissolved in a liquid or an aqueous solution, the equilibrium constant is used in equations.
  • Hg 2 I 2 ---Hg2^{2+}  +2I^{-}
  • HereHg = s and 2I- = 2s
  • For finding the solubility product K sp = [Hg^{2+} ][I^{-} ]2

the solubility of Hg2I2 in water is

Ksp=[s][2s]^{2}

  • Ksp=4s^{3} =4[10^{-5}]=4×10^{-5}
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