The solubility of L(OH)2 in water is 2.5 x 10 –4 mol/ L, the pH of L(OH)2 is ….
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Answer:
ph = 3.3
Explanation:
L(OH)2 gives L+2OH
OH formed = 5 x10^-4
additional OH due to h20 = 10^-7
ph = -log(5x10^-4+10^-7) = 3.3
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