Chemistry, asked by abc2808, 7 months ago

· The solubility of lead iodide in water is 0.63 g/litre. Calculate the solubility product of lead iodide. (At mass
of Pb = 207, I = 127)

Answers

Answered by joseanagha

0

Answer:

1.02 MULTIPLY BY 10 NEGATIVE 8

Explanation:

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