the solubility of mg(OH)2 at 298k is 1.5×10^-4.calculate the solubility product
Answers
Explanation:
Magnesium hydroxide,
Mg
(
OH
)
2
, is considered Insoluble in aqueous solution, which implies that the ions it forms will be in equilibrium with the solid.
Magnesium hydroxide dissociates only partially to form magnesium cations,
Mg
2
+
, and hydroxide anions,
OH
−
Mg
(
OH
)
2(s]
⇌
Mg
2
+
(aq]
+
2
OH
−
(aq]
Magnesium hydroxide, Mg(OH)2, is considered Insoluble in aqueous solution, which implies that the ions it forms will be in equilibrium with the solid.Magnesium hydroxide dissociates only partially to form magnesium cations, Mg2+, and hydroxide anions, OH−Mg(OH)2(s]⇌Mg2+(aq]+2OH−(aq]For an insoluble compound, its molar solubility tells you how many moles of the compound can be dissolved per liter of aqueous solution before reaching saturation.In your case, a molar solubility ofs=1.6⋅10−4means that you can only dissolve 1.6⋅10−4 moles of magnesium in a liter of water at that temperature.Take a look at the dissociation equilibrium. Notice that every mole of magnesium hydroxide that dissociates produces 1 mole of magnesium cations and 2 moles of hydroxide anions.This tells you that if you successfully dissolve 1.6⋅10−4 moles of magnesium hydroxide in one liter of solution, number of moles of each ion will be