Question

the solubility of Mg(OH)2 is 11.6 into 10 to the power minus 2 gram per litre at 298 degrees Celsius find out its solubility product at this temperature.​

Answer 1

Answer:

Mg(OH)2 --> Mg^+2 + 2 OH-

Ksp = [Mg^+2][OH-]^2

let x = [Mg^+2], then [OH] = 2x

Ksp = (1.2x10^-4)(2.4x10^-4)^2

Ksp = 6.9x10^-12

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