Question

The solubility of N2(g) at 593 mm of Hg is 5.3x10^-4
in water. Its solubility at 860 mm and at the same
temperature in water is
(1) 5.3 × 10^-4
(2) 7.68 10^-4
(3) 9.0 × 10^-4 (4) 1.2 × 10^-3​

Answer 1

Given:

The solubility of N2, X1 = 5.3 × 10⁻⁴

The pressure, P1 = 593 mm Hg

The new pressure, P2 = 860 mm Hg

To Find:

The new solubility of N2 gas, i.e., X2.

Calculation:

- According to Henry's law, we have:

P1 = $K_{H}$X1

⇒ $K_{H}$ = P1/X1

⇒ $K_{H}$ = 593/5.3 × 10⁻⁴

- Again applying Henry's law, we have:

P2 = $K_{H}$X2

⇒ X2 = P2/$K_{H}$

⇒ X2 = 860/(593/5.3 × 10⁻⁴)

⇒ X2 = 860 × 5.3 × 10⁻⁴/593

⇒ X2 = 7.68 × 10⁻⁴

- So, the correct answer is option (2) 7.68 × 10⁻⁴.