Question

The solubility of n2 in water at 300k and 500k torr

Answer 1

Solubility is 0.015

Explanation:

According to Henry's law,

$C = K \times P$

where, C = Solubility of gas

K = Proportionality Constant

P = Pressure = 500 torr

C = $0.01\ gL^-^1$

K = $\frac {C}{P}\\= \frac {0.01}{500}$

K = 0.00002  

Now, solubility at 750 torr

C = $K \times P$

C = $0.00002 \times 750$

C = 0.015