Question

The solubility of oxygen in water is 2.43×10−32.43×10−3mol/dm3 at 25degree C and 1 atm pressure. Calculate the concentration of oxygen at 25degreeC and 0.2 atm pressure.​

Answer 1

Answer:

written below-

Explanation:

According to Henry s law, C=KH p

where, C= concentration, p= pressureand KH= Henry s law constant.

∴ KH=C/p=2.43×10^{-3}/1.0=2.43×10^{-3} mol L^{-1} atm^{-1}

further C=KHp or C=2.43×10^{-3}×0.2 Concentration =4.86×10^{-4} mol L^{-1} `

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