Chemistry, asked by anonymous18762e0, 3 months ago

The solubility of potassium nitrate is 106 gm at 333k. Its solubility at 283 k is 21 gm.If its saturted solution at 333k in 50 gm water is cooled to 283k. What amount of salt can be precipitated out?Pls answer fast

Answers

Answered by mahtibin
2

Answer:

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Answered by jassi1178
3

Answer:

(a) At 313 K 62 g of potassium nitrate dissolved in 100 g of water. So to produce a saturated solution of potassium nitrate in 50 g of water we need

100

62

×50=31 g of potassium nitrate.

(b)Some soluble potassium chloride will separate out in the form of crystal at room temperature because the solubility of potassium chloride will decrease.

(c)

(i) Solubility of Potassium nitrate at 293 K is 32 g.

(ii) Solubility of sodium chloride at 293 K is 36 g.

(iii) Solubility of Potassium chloride at 293 K is 35 g.

(iv) Solubility of Ammonium chloride at 293 K is 37 g.

The solubility of Ammonium chloride is highest at this temperature.

(d)The solubility of salt increases with the increase in temperature.

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