Question

the solubiliTy of salt in water at 25°c is 155 . when 80 gram of its saturated Solution at 25°c was cooled to 15°c , 40 gram of salt was precipeted . find The solubility of salt at 15°C . ​

Answer 1

Answer:

Explanation:

weight of salt = 90 gram,

solubility  = 50

sing formula

solubility of solute = Weight solute in saturated solution       × 100

                                 Weight of solvent in saturated solution

or 50  =                       90gm                                                        

                    Weight of solvent in saturated solution

so weight of solvent in saturated solution = $\frac{90gm}{50}$ × 100 = 180gm

Hence 180 gm of water is required to prepare a saturated solution.