Question

The solubility of
silver chloride at 25°c
is 1.05 x 10^-5
moles
per
letre
.
Calculate the stublility product if the
salt is 80% dissociated in its saturated
solution 3mark
Anst​

Answer 1

Explanation:

Let the solubility of AgCl be S mol litre

−1

AgCl⇌Ag

+

+Cl

−

Hence, S

2

=1.5625×10

−10

or S=1.25×10

−5

molL

−1

molecular mass of AgCl=(108+35.5)=143.5

So, Solubility in g litre

−1

=Mol mass×S=1.79×10

−3

gL

−1