The solubility ( per 100 g) of some unknown salt at 25°C is 25 g. Mohan made a
saturated solution of this salt using 300 g of water at the same temperature.
From this solution, 50 g solution was removed and the temperature of the rest
solution was increased to 35°C 25 g more salt is added to it to make this a
saturated solution at 35°C. The concentration (w/w) of this saturated solution at
35°C will be
Answers
Answer:
(a) At 313 K 62 g of potassium nitrate dissolved in 100 g of water. So to produce a saturated solution of potassium nitrate in 50 g of water we need
100
62
×50=31 g of potassium nitrate.
(b)Some soluble potassium chloride will separate out in the form of crystal at room temperature because the solubility of potassium chloride will decrease.
(c)
(i) Solubility of Potassium nitrate at 293 K is 32 g.
(ii) Solubility of sodium chloride at 293 K is 36 g.
(iii) Solubility of Potassium chloride at 293 K is 35 g.
(iv) Solubility of Ammonium chloride at 293 K is 37 g.
The solubility of Ammonium chloride is highest at this temperature.
(d)The solubility of salt increases with the increase in temperature