The solubility product of a rare earth metal hydroxide m(oh)3 at room temperature is 4.32*10-14. Its solubility is
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So, the compound dissolves by the equation:
M(OH)3 <--> M3+ + 3 OH-
Ksp = [M3+][OH-]^3 = 4.32 X 10^-14
Let x = molar solubility of M(OH)3. Then, in a saturated solution, [M3+] = x and [OH-] = 3x. Plugging those into the expression for Ksp gives:
Ksp = 4.32 X 10^-14 = (x)(3x)^3 = 27x^4
x = 2X10^-4
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