Question

The solubility product of a salt ab2 is 4*10^-9 at 373k.The solubility of ab2 in boiling water will be

Answer 1

Answer:

Solubility (s) of salt ab2 at 373 k = 6.3 X 10⁻⁶ mol/L

Explanation:

Given

Solubility product (ksp) = 4 X 10⁻⁹

Temperature = 373 k

Solubility = ??

Solution

The solubility product  (ksp) of ab2 =  4 X 10⁻⁹

as we know that, the relation between Solubility (s) and  solubility product  (ksp) can be written as

ksp =s²

since water boils at 100 °C that is equivalent to 373 k.

Therefore,

Solubility (s) = √4 X 10⁻⁹

Solubility (s) = 6.3 X 10⁻⁶ mol/L

Solubility (s) of salt ab2 at 373 k = 6.3 X 10⁻⁶ mol/L