Question

The solubility product of a salt having the formula m2x3 is 1 *10^-20 if the solubility of of an another salt having the formula m2x is twice the molar solubility of m2x3 the solubility product of m2x is
Anyone solve it

Answer 1

Answer:

Explanation:

As we know for calculating solubility(s) ,

S=[Ksp/X^x Y^y]^1/x+y

So for M2X3 we have, s =[ ksp/108 ]^1/5

It gives us S which can be used for the 2nd rxn,

i.e.for M2X , we have ,

S= [ksp/4]^1/3

OR

ksp=4S^3

It will give u Ksp=3×10^-12

Hope this will help you!