Chemistry, asked by jeannie1818, 9 months ago

The solubility product of a sparingly soluble salt AX is 5.2×10^(-13). Its solubility in mol dm^(-3)​

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Answers

Answered by rockstar2019
14

Answer:

A] 7.2 × 10-

Explanation:

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Answered by krishna210398
2

Answer:

Option a)7.2x10^-7

Explanation:

Let 's' be the solubility of a salt consisting of AX 2

​ which undergoes dissociation as follows  :-

                 AX 2→A +2 +2X −

(Solubility)   1-s          s   2s

Thus, the solubility product K sp  is s×(2s) 2

∴K sp =4s three

∴5.2×10 10 =4s three

∴s three = 43.2×10 10

∴s three =0.8×10 10

Thus taking dice root on each the perimeters we get,

s=2×10 three  

The solubility made from a sparingly soluble salt AX is 5.2 × 10-13. Its solubility in mol dm-three is 7.2 × 10-7.Λm = (κ x 1000)/c

'c' is the awareness of the salt in eq/l and as a result the solubility of the salt. Since the salt is sparingly soluble, the answer could be very dilute and Λm can be taken into consideration to be identical to Λ0m i.e., the molar conductance at endless dilution.

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