Science, asked by devanandshilpa7341, 1 year ago

The solubility product of a sparingly soluble salt AX2 is 3.2×10−11. Its solubility (in moles/litre) is:-

Answers

Answered by sumedha2302gmailcom
5

let the solubility be x,

AX2=A+ +2X-

S. 2S

ksp=s×(2s)^2

=4s^3

3.2×10-11=4s^3

8×10-12=s^3

s=2×10-4


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