Question

The solubility product of AgBr is 4.9 ×10^-9.The solubility of AgBr will be:(1)7×10^-4mole/litre, (2)7×10^-5g/litre, (3)1.316×10^-2g/litre, (4)1×10^-3mole/litre

Answer 1

2nd option is the answer

$7 \times {10}^{ - 5} g \: ( {litre})^{ - 1}$