Question

The solubility product of AgCl is 2.0 X 10-10 mol2 dm-6. The maximum concentration of Ag+ ions in the solution is ?​

Answer 1

Answer:

1.414 x 10-5 mol dm-3

Explanation:

solubility product for AgCl = [Ag+]×[Cl-]

2.0×10^(-10) mol² dm^(-6) = [Ag+] × [Cl-]

[Ag+] = 2.0×10^(-10) ÷ [Cl-] mol dm^(-3)

here, concentration of Cl ion , i.e., [Cl-] , is that given in solutions ( whose value has not been given here)

put the value of [Cl-] , u will get your answer

And correct answer is 1.414 x 10-5 mol dm-3